![]() ![]() ![]() IMHO it is very unlikely that this is the full or the correct story, as there are much better options for a signal which must travel, reliably, perhaps over long wires, back to the control panel.Ī door being open vs. a door is open, a motion detector detects motion) the corresponding pin goes from 0V to about 0.3V. I have snooped on the control box with a voltmeter and it looks like when a sensor is tripped (i.e. Another idea I've considered is to implement a voltage comparator with Vref at 0.15V) Simulate this circuit – Schematic created using CircuitLabĪny ideas on why my circuit is behaving like this? (Or if you have another way of solving the problem, that would help too. (Another data point: when I tested with V1 set to 3.3V but everything else the same, the Output stayed at a constant 2.1V) However, when I implement the circuit on a breadboard the output stays at a constant 3.9V, regardless of if I implement the circuit as designed or disconnect the V0 input. When I simulate the circuit, it works exactly as I intend. Using the op amp as a non-inverting amplifier, and choosing my resistors as shown in the schematic below, I should see a gain of 11, which should give Output = V0 * 11. My idea is to use an op amp (I have a couple of LM2902N's lying around) to multiply the voltage. What I would like to do is monitor the pins with my RPi, so I figure that the input voltages to the RPi will need to range from 0V to 3.3V in order to work with the GPIO pins. ![]() Much like this question, I am trying to interface a Raspberry Pi 3 Model B to an alarm system, but this time is is a GE NetworX NX-8V2. ![]()
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